Optimizing Score Distribution for Maximum Efficiency

Optimizing Score Distribution for Maximum Efficiency

In this piece, we explore the math behind a specific problem to gain insights into optimal score distribution and the importance of understanding averages in various contexts. Our journey will involve breaking down the problem, applying mathematical principles, and providing a clear solution that underscores the practical application of mathematical concepts in daily scenarios.

Setting Up the Problem

Consider a student who scored a total of 600 in 12 tests. In four of these tests, he achieved 80 percent of his average score per test. Given that he did not score more than 60 in any of the tests, the question is: in how many of the remaining eight tests should he have scored more than 50 to achieve the desired average?

Calculating the Average Score Per Test

To begin, we need to determine the average score per test. The total score is 600 over 12 tests, so the average score per test is:

Average score per test Total score / Number of tests 600 / 12 50.

Now, we know that the average score per test is 50. For four of these tests, he achieved 80 percent of this average score:

Score in four tests 0.8 × Average score 0.8 × 50 40.

The total score for these four tests is:

Total score in four tests 4 × 40 160.

Calculating the Remaining Score for the Other Eight Tests

Subtracting the score of the four tests from the total score gives us the remaining score for the other eight tests:

Total score in remaining eight tests Total score - Total score in four tests 600 - 160 440.

Understanding the Average Score for the Remaining Eight Tests

The average score for the remaining eight tests is therefore:

Average score for remaining eight tests Total score in remaining tests / Number of remaining tests 440 / 8 55.

Constraints on Test Scores

It is given that no score exceeded 60 in any of the tests. To find the minimum number of tests in which the score was more than 50, we need to analyze the possible scores. Assume that the number of tests with scores more than 50 is denoted as x, and those with scores of 50 or less is 8 - x.

If x tests score more than 50, the maximum score for each of these tests is 60 (assuming the minimum score of these is 51). The contribution to the total score from the tests scoring more than 50 is:

Max contribution from these tests x × 60.

The contribution from the remaining 8 - x tests scoring 50 or less must be:

Contribution from the remaining tests 440 - x × 60.

Since the maximum score for these tests is 50, we have:

440 - x × 60 ≤ (8 - x) × 50.

Setting Up the Inequality

Rearranging the inequality, we get:

440 - 400 ≥ 6 - 5,

40 ≥ 1,

x ≥ 4.

This means that the minimum number of tests in which the score should be more than 50 is 4.

Conclusion

The solution to the problem highlights the importance of understanding how to distribute scores for optimal performance. By breaking down the problem step-by-step and applying mathematical principles, we can determine the minimum number of tests that need to score more than 50 to achieve an average score effectively.

Understanding and optimizing score distribution can be applied in various real-world scenarios, including academic and professional settings. Whether it's maximizing test scores, optimizing resource allocation, or achieving specific performance targets, the principles outlined in this article can provide valuable insights.